[ITA - 2013 - 1 FASE] Considere \(A \epsilon M_{5x5}(\mathbb{R})\) com \(det(A)=\sqrt{6}\) e \(\alpha \epsilon \mathbb{R}\)\ {0}. Se \(det(\alpha A^tAA^t)=\sqrt{6}\alpha ^2\), o valor de \(\alpha\) é
\(\frac{1}{6}\)
\(\frac{\sqrt6}{6}\)
\(\frac{\sqrt[3]{36}}{6}\)
\(1\)
\(\sqrt {216}\)