(ITA - 2018 - 1 FASE)
Se log2π = a e log5 π = b, então
\(\frac{1}{a}+\frac{1}{b}\leq \frac{1}{2}.\)
\(\frac{1}{2}< \frac{1}{a}+\frac{1}{b}\leq 1\)
\(1< \frac{1}{a}+\frac{1}{b}\leq \frac{3}{2}\)
\(\frac{3}{2}< \frac{1}{a}+\frac{1}{b}\leq 2\)
\(2< \frac{1}{a}+\frac{1}{b}.\)